Clausius-Clapeyron Vapor Pressure Calculator


Clausius-Clapeyron Vapor Pressure Calculator

Calculate Vapor Pressure

This tool uses the Clausius-Clapeyron equation to estimate the vapor pressure of a liquid at a given temperature when a reference point is known.



The known vapor pressure of the substance in Pascals (Pa). Default is 1 atm.

Please enter a valid positive number.



The temperature in Celsius (°C) at which the vapor pressure P₁ is known. Default is the boiling point of water.

Please enter a valid number.



The temperature in Celsius (°C) for which you want to calculate the new vapor pressure.

Please enter a valid number.



The molar enthalpy of vaporization of the substance in Joules per mole (J/mol). Default is for water.

Please enter a valid positive number.


Calculated Vapor Pressure (P₂)

— Pa

Intermediate Values

T₁ in Kelvin

— K

T₂ in Kelvin

— K

ln(P₂/P₁)

Formula Used: P₂ = P₁ * exp(- (ΔHvap / R) * (1/T₂ – 1/T₁)), where R = 8.314 J/(mol·K).

Chart of Vapor Pressure vs. Temperature for the given substance.

What is the Clausius-Clapeyron Vapor Pressure Calculator?

The Clausius-Clapeyron Vapor Pressure Calculator is a specialized tool designed to model the relationship between the vapor pressure of a liquid and its temperature. Vapor pressure is a fundamental property of matter that describes the pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases (solid or liquid) at a given temperature in a closed system. This concept is crucial in fields like chemistry, physics, and engineering. Anyone studying or working with phase transitions, such as boiling, condensation, or sublimation, will find this calculator invaluable. A common misconception is that a liquid only evaporates at its boiling point; in reality, evaporation occurs at any temperature, and the Clausius-Clapeyron equation helps quantify the resulting pressure.

Clausius-Clapeyron Formula and Mathematical Explanation

The relationship between vapor pressure and temperature is not linear. The Clausius-Clapeyron equation provides a way to approximate this relationship by relating the latent heat (enthalpy) of vaporization, temperature, and vapor pressure. The two-point form of the equation is most commonly used by this Clausius-Clapeyron Vapor Pressure Calculator:

ln(P₂ / P₁) = – (ΔHvap / R) * (1/T₂ – 1/T₁)

This equation allows you to calculate the vapor pressure (P₂) at a specific temperature (T₂) if you already know the vapor pressure (P₁) at a different temperature (T₁), along with the substance’s molar enthalpy of vaporization (ΔHvap). The constant R is the ideal gas constant. To find the unknown pressure P₂, the formula is rearranged: P₂ = P₁ * exp(- (ΔHvap / R) * (1/T₂ – 1/T₁)). This is the core calculation performed by our thermodynamics calculator.

Variables in the Clausius-Clapeyron Equation
Variable Meaning Unit Typical Range
P₁, P₂ Vapor Pressure at points 1 and 2 Pascals (Pa), atm, mmHg Varies widely
T₁, T₂ Absolute Temperature at points 1 and 2 Kelvin (K) ~100 K to 1000 K
ΔHvap Molar Enthalpy of Vaporization Joules per mole (J/mol) 20,000 to 50,000 J/mol
R Ideal Gas Constant J/(mol·K) 8.3145

Practical Examples (Real-World Use Cases)

Example 1: Vapor Pressure of Water on a Mountain

Imagine you are climbing a mountain and want to know the boiling point of water. We can use the Clausius-Clapeyron Vapor Pressure Calculator in reverse. Let’s say atmospheric pressure is 85,000 Pa. We know water’s normal boiling point is 100°C (373.15 K) at 101,325 Pa, and its enthalpy of vaporization is about 40,700 J/mol.

  • Inputs: P₁ = 101325 Pa, T₁ = 373.15 K, P₂ = 85000 Pa, ΔHvap = 40700 J/mol.
  • Calculation: Rearranging the formula to solve for T₂, we get T₂ = [1/T₁ – (R * ln(P₂/P₁)) / ΔHvap]⁻¹
  • Output: The calculator would show that the new boiling temperature (T₂) is approximately 95.1°C. This demonstrates why cooking takes longer at high altitudes.

Example 2: Vapor Pressure of Ethanol

A chemist is working with ethanol in a closed system at 50°C and wants to predict the pressure inside the container. They know that the normal boiling point of ethanol is 78.4°C at 101,325 Pa, and its enthalpy of vaporization (ΔHvap) is approximately 38,600 J/mol.

  • Inputs: P₁ = 101325 Pa, T₁ = 78.4°C (351.55 K), T₂ = 50°C (323.15 K), ΔHvap = 38600 J/mol.
  • Calculation: Using the standard formula with the provided inputs.
  • Output: The Clausius-Clapeyron Vapor Pressure Calculator predicts the vapor pressure P₂ will be around 29,500 Pa. This information is vital for safety and equipment design. Understanding the vapor pressure formula is key here.

How to Use This Clausius-Clapeyron Vapor Pressure Calculator

Using this calculator is straightforward and provides instant, accurate results for your thermodynamics problems. Follow these simple steps:

  1. Enter Known Pressure (P₁): Input the reference vapor pressure in Pascals (Pa). For many substances, this is standard atmospheric pressure (101,325 Pa) at their normal boiling point.
  2. Enter Known Temperature (T₁): Input the corresponding reference temperature in Celsius (°C).
  3. Enter Target Temperature (T₂): Input the temperature in Celsius (°C) for which you want to find the new vapor pressure.
  4. Enter Enthalpy of Vaporization (ΔHvap): Provide the molar enthalpy of vaporization for your substance in J/mol. This is a critical factor and unique to each liquid. A good resource for this is our guide on understanding enthalpy of vaporization.
  5. Read the Results: The calculator automatically updates, showing the final vapor pressure (P₂) in the highlighted green box. You can also review key intermediate values like the temperatures in Kelvin.

This tool helps in making informed decisions, whether for academic purposes, laboratory safety, or engineering design. A higher predicted pressure might mean a stronger container is needed.

Key Factors That Affect Vapor Pressure Results

Several factors critically influence the results from a Clausius-Clapeyron Vapor Pressure Calculator. Understanding them provides deeper insight into the physics of phase transition thermodynamics.

  • Temperature: This is the most significant factor. As temperature increases, the kinetic energy of molecules increases, allowing more of them to escape the liquid phase and become vapor, thus increasing vapor pressure.
  • Enthalpy of Vaporization (ΔHvap): This represents the energy required to transform a mole of liquid into a gas. It’s a measure of the strength of intermolecular forces. Substances with stronger forces (e.g., hydrogen bonds in water) have a higher ΔHvap and a lower vapor pressure at a given temperature compared to substances with weaker forces (e.g., London dispersion forces in hexane).
  • Intermolecular Forces: Directly related to ΔHvap, the type and strength of forces holding liquid molecules together (hydrogen bonding, dipole-dipole, etc.) determine how easily molecules can escape into the vapor phase.
  • Molar Mass: Generally, for substances with similar intermolecular forces, those with lower molar mass tend to have higher vapor pressures because the molecules are lighter and move faster at a given temperature.
  • Purity of the Substance: The presence of non-volatile solutes in a liquid lowers its vapor pressure. This phenomenon is described by Raoult’s Law. This calculator assumes a pure substance.
  • Reference Point Accuracy: The accuracy of the calculation is highly dependent on the accuracy of the known P₁ and T₁ values. Using a certified normal boiling point as the reference yields the best results.

Frequently Asked Questions (FAQ)

1. What are the main limitations of the Clausius-Clapeyron equation?

The equation assumes that the enthalpy of vaporization (ΔHvap) is constant over the temperature range, which is only an approximation. It also assumes the vapor behaves as an ideal gas and that the molar volume of the liquid is negligible compared to the vapor. These assumptions break down over very large temperature ranges or near the critical point. For more precise calculations over wide ranges, equations like the Antoine equation are often used, which is a key part of any good boiling point calculator.

2. Can I use this calculator for solids (sublimation)?

Yes, the principle is the same. You would need to use the enthalpy of sublimation (ΔHsub) instead of the enthalpy of vaporization. The form of the equation remains identical, modeling the pressure of the vapor in equilibrium with the solid.

3. Why do I need to use Kelvin for temperature in the formula?

Thermodynamic equations like this one require absolute temperatures (Kelvin) because they relate directly to the kinetic energy of molecules. Using Celsius or Fahrenheit would lead to incorrect results because their zero points are arbitrary and not representative of zero kinetic energy.

4. Where can I find the enthalpy of vaporization for a substance?

The enthalpy of vaporization is an empirical value that can be found in chemistry textbooks, scientific handbooks (like the CRC Handbook of Chemistry and Physics), or online chemical databases. Our Clausius-Clapeyron Vapor Pressure Calculator defaults to water for convenience.

5. How is this different from a boiling point calculator?

A boiling point calculator typically solves for temperature when a certain pressure is given. This Clausius-Clapeyron Vapor Pressure Calculator solves for pressure at a given temperature. They use the same underlying formula, just rearranged to solve for a different variable.

6. Does atmospheric pressure affect the calculation?

The calculation itself is independent of the external atmospheric pressure. It calculates the inherent equilibrium vapor pressure of a substance in a closed container. However, a liquid boils when its vapor pressure equals the external pressure, so atmospheric pressure is critical for determining the boiling point.

7. What is the ‘R’ constant in the formula?

R is the Ideal Gas Constant. Its value depends on the units used for pressure and volume. In the context of this calculator, where energy is in Joules, its value is 8.3145 J/(mol·K). It’s a fundamental constant in physics and chemistry.

8. Why does the vapor pressure curve get steeper at higher temperatures?

The relationship is exponential, not linear. As temperature rises, a small increase in temperature leads to a much larger increase in vapor pressure. This is because a greater fraction of molecules has sufficient energy to overcome intermolecular forces, leading to a rapid rise in vapor concentration and pressure. This is well-visualized by the thermodynamics calculator chart.

Related Tools and Internal Resources

For further exploration into thermodynamics and chemical properties, consider these resources:

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